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]8..^ERR~7N]d!ERER]..^ERR~7N]d!ERER]..^ERR~7N]d!ERERR]`.]`.^ERR~7N]d!ERER].]`.^ERR~7N]d!ERER].]`.^ERR~7N]d!ERER].]`.^ER R~7N]d!ER!ER"]!.]`.^ER#R~7N]d!ER$ER%R]S]S.]`.^ER&R~7N]d!ER'ER(R]`]`.]`.^ER)R~7N]d!ER*ER+R]`]`.]`.^ER,R~7N]d!ER-ER.]!]a]b.]`.^ER/R~7N]d!ER0ER1R]a]`]b.]`.^ER2R~7N]d!ER3ER4R]`]`.]`.^ER5R~7N]d!ER6ER7R]`]`]`.]`.^ER8R~7N]d!ER9ER:]..^ER;R~7N]d!ER<ER=R]`..^ER>R~7N]d!ER?ER@]..^ERAR~7N]d!ERBERC].]`.^ERDR~7N]d!EREERFR]`.]`.^ERGR~7NteAd/tf/tg]h!]e4F�wtitj]jP�]f9d/]l!ERH]jP�]f]jP�,]i3,4h]jP�]g9d/]l!ERI]jP�]g]jP�,]i3,4h]i]f]jP�&]i]g]jP�&K�	AfAgAiAj/tn]eFtj]j]n]jP�&K	AjER~ERJlto]o!4AoER~ERKltpERLtqERMtrERERNlts!EROERP4ttERQtuERRtvERS]uERT]v/tw]xERU8XEd$^RIyty]yP�!ERVRERW7t{]{P�ERXERYERZER[7]{P�ER\ER]ER^ER_7]{P�ER`ERaERbERcERd7]{P�EReERf^]DERgERh7]{P�ERiERjERbERkERd7]{P�ERlERmERnERoERp7]{P�4t~]~P�'d^M^t]~EP'd/MRt�]~EPf]EPt�M]�!]~EPERq4t�]~EPF�t�]�!]~EP4^8�dG]�ERr8XdERsM]�tk]~EPEP]kERt7t�]�EP]�ERu,4]�ERr8Xd0]s!]EPEP]�]�]~EP]4K�]�!]�ERv4;_uu_4t�]s!]�]�]�]~EP]4RRR4K�	]�]EPJd]�EP4R#R#R# +'giEK;i ]�]EPJd]�EP4ii;i(�ar"Executable documentation" for the pickle module.

Extensive comments about the pickle protocols and pickle-machine opcodes
can be found here.  Some functions meant for external use:

genops(pickle)
   Generate all the opcodes in a pickle, as (opcode, arg, position) triples.

dis(pickle, out=None, memo=None, indentlevel=4)
   Print a symbolic disassembly of a pickle.
Nc�*a�]tRt^�toRtRtRtVtR#)�ArgumentDescriptorc��\V\4'gQhWn\V\4'd(V^8�g#V\\
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>>> import io
>>> read_uint1(io.BytesIO(b'\xff'))
255
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�6�6�!�9�D���A�w��
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?�?r�uint1zOne-byte unsigned integer.rc��VP^4p\V4^8Xd\RV4^,#\R4h)zi
>>> import io
>>> read_uint2(io.BytesIO(b'\xff\x00'))
255
>>> read_uint2(io.BytesIO(b'\xff\xff'))
65535
z<Hz'not enough data in stream to read uint2�r$�len�_unpackr%r&s& r�
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?�?r�uint2z)Two-byte unsigned integer, little-endian.c��VP^4p\V4^8Xd\RV4^,#\R4h)z�
>>> import io
>>> read_int4(io.BytesIO(b'\xff\x00\x00\x00'))
255
>>> read_int4(io.BytesIO(b'\x00\x00\x00\x80')) == -(2**31)
True
z<iz&not enough data in stream to read int4r,r&s& r�	read_int4r3�s:��
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>>> import io
>>> read_uint4(io.BytesIO(b'\xff\x00\x00\x00'))
255
>>> read_uint4(io.BytesIO(b'\x00\x00\x00\x80')) == 2**31
True
z<Iz'not enough data in stream to read uint4r,r&s& r�
read_uint4r6r0r�uint4z*Four-byte unsigned integer, little-endian.c��VP^4p\V4^8Xd\RV4^,#\R4h)z�
>>> import io
>>> read_uint8(io.BytesIO(b'\xff\x00\x00\x00\x00\x00\x00\x00'))
255
>>> read_uint8(io.BytesIO(b'\xff' * 8)) == 2**64-1
True
z<Qz'not enough data in stream to read uint8r,r&s& r�
read_uint8r9&r0r�uint8z+Eight-byte unsigned integer, little-endian.T�encoding�latin-1c��VP4pVPR4'g\R4hVRRpV'ddRFKpVPV4'gKVPV4'g\RV:RV:24hV^RpM	\RV,4hV'd-\P
!V4^,P
V4pV#)	a)
>>> import io
>>> read_stringnl(io.BytesIO(b"'abcd'\nefg\n"))
'abcd'

>>> read_stringnl(io.BytesIO(b"\n"))
Traceback (most recent call last):
...
ValueError: no string quotes around b''

>>> read_stringnl(io.BytesIO(b"\n"), stripquotes=False)
''

>>> read_stringnl(io.BytesIO(b"''\n"))
''

>>> read_stringnl(io.BytesIO(b'"abcd"'))
Traceback (most recent call last):
...
ValueError: no newline found when trying to read stringnl

Embedded escapes are undone in the result.
>>> read_stringnl(io.BytesIO(br"'a\n\\b\x00c\td'" + b"\n'e'"))
'a\n\\b\x00c\td'
�
z-no newline found when trying to read stringnlNz
string quote z not found at both ends of zno string quotes around %r���)�"�')�readline�endswithr%�
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�:�:�<�D��=�=�����H�I�I����9�D���A����q�!�!��}�}�Q�'�'�$�56��&>�?�?��A�b�z���
��9�D�@�A�A�
��#�#�D�)�!�,�3�3�H�=���Kr�stringnlz�A newline-terminated string.

                   This is a repr-style string, with embedded escapes, and
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                   c��\VRRR7#)F�utf-8)rHr;)rJ�r's&r�read_stringnl_noescaperOts������@�@r�stringnl_noescapeaA newline-terminated string.

                        This is a str-style string, without embedded escapes,
                        or bracketing quotes.  It should consist solely of
                        printable ASCII characters.
                        c�8�\V4:R\V4:2#)z`
>>> import io
>>> read_stringnl_noescape_pair(io.BytesIO(b"Queue\nEmpty\njunk"))
'Queue Empty'
� )rOrNs&r�read_stringnl_noescape_pairrS�s��-�Q�/�1G��1J�K�Kr�stringnl_noescape_paira�A pair of newline-terminated strings.

                             These are str-style strings, without embedded
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                             consist solely of printable ASCII characters.
                             The pair is returned as a single string, with
                             a single blank separating the two strings.
                             c���\V4pV^8�gQhVPV4p\V4V8XdVPR4#\	RV\V43,4h)zj
>>> import io
>>> read_string1(io.BytesIO(b"\x00"))
''
>>> read_string1(io.BytesIO(b"\x03abcdef"))
'abc'
r<z2expected %d bytes in a string1, but only %d remain)r)r$r-rGr%�r'rr(s&  r�read_string1rW�s_��	�1�
�A���6�M�6��6�6�!�9�D�
�4�y�A�~��{�{�9�%�%�
�I���T��^�$�%�%r�string1z�A counted string.

              The first argument is a 1-byte unsigned int giving the number
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              bytes.
              c���\V4pV^8d\RV,4hVPV4p\V4V8XdVP	R4#\RV\V43,4h)a(
>>> import io
>>> read_string4(io.BytesIO(b"\x00\x00\x00\x00abc"))
''
>>> read_string4(io.BytesIO(b"\x03\x00\x00\x00abcdef"))
'abc'
>>> read_string4(io.BytesIO(b"\x00\x00\x00\x03abcdef"))
Traceback (most recent call last):
...
ValueError: expected 50331648 bytes in a string4, but only 6 remain
zstring4 byte count < 0: %dr<z2expected %d bytes in a string4, but only %d remain)r3r%r$r-rGrVs&  r�read_string4rZ�sl��	�!��A��1�u��5��9�:�:��6�6�!�9�D�
�4�y�A�~��{�{�9�%�%�
�I���T��^�$�%�%r�string4z�A counted string.

              The first argument is a 4-byte little-endian signed int giving
              the number of bytes in the string, and the second argument is
              that many bytes.
              c��\V4pV^8�gQhVPV4p\V4V8XdV#\RV\V43,4h)zj
>>> import io
>>> read_bytes1(io.BytesIO(b"\x00"))
b''
>>> read_bytes1(io.BytesIO(b"\x03abcdef"))
b'abc'
z1expected %d bytes in a bytes1, but only %d remain)r)r$r-r%rVs&  r�read_bytes1r]�sU��	�1�
�A���6�M�6��6�6�!�9�D�
�4�y�A�~���
�H���T��^�$�%�%r�bytes1z�A counted bytes string.

              The first argument is a 1-byte unsigned int giving the number
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              c��\V4pV^8�gQhV\P8�d\RV,4hVP	V4p\V4V8XdV#\RV\V43,4h)a&
>>> import io
>>> read_bytes4(io.BytesIO(b"\x00\x00\x00\x00abc"))
b''
>>> read_bytes4(io.BytesIO(b"\x03\x00\x00\x00abcdef"))
b'abc'
>>> read_bytes4(io.BytesIO(b"\x00\x00\x00\x03abcdef"))
Traceback (most recent call last):
...
ValueError: expected 50331648 bytes in a bytes4, but only 6 remain
z#bytes4 byte count > sys.maxsize: %dz1expected %d bytes in a bytes4, but only %d remain)r6�sys�maxsizer%r$r-rVs&  r�read_bytes4rb�sq��	�1�
�A���6�M�6��3�;�;���>��B�C�C��6�6�!�9�D�
�4�y�A�~���
�H���T��^�$�%�%r�bytes4z�A counted bytes string.

              The first argument is a 4-byte little-endian unsigned int giving
              the number of bytes, and the second argument is that many bytes.
              c��\V4pV^8�gQhV\P8�d\RV,4hVP	V4p\V4V8XdV#\RV\V43,4h)a�
>>> import io, struct, sys
>>> read_bytes8(io.BytesIO(b"\x00\x00\x00\x00\x00\x00\x00\x00abc"))
b''
>>> read_bytes8(io.BytesIO(b"\x03\x00\x00\x00\x00\x00\x00\x00abcdef"))
b'abc'
>>> bigsize8 = struct.pack("<Q", sys.maxsize//3)
>>> read_bytes8(io.BytesIO(bigsize8 + b"abcdef"))  #doctest: +ELLIPSIS
Traceback (most recent call last):
...
ValueError: expected ... bytes in a bytes8, but only 6 remain
z#bytes8 byte count > sys.maxsize: %dz1expected %d bytes in a bytes8, but only %d remain)r9r`rar%r$r-rVs&  r�read_bytes8resq��	�1�
�A���6�M�6��3�;�;���>��B�C�C��6�6�!�9�D�
�4�y�A�~���
�H���T��^�$�%�%r�bytes8z�A counted bytes string.

              The first argument is an 8-byte little-endian unsigned int giving
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              c�
�\V4pV^8�gQhV\P8�d\RV,4hVP	V4p\V4V8Xd\
V4#\RV\V43,4h)a�
>>> import io, struct, sys
>>> read_bytearray8(io.BytesIO(b"\x00\x00\x00\x00\x00\x00\x00\x00abc"))
bytearray(b'')
>>> read_bytearray8(io.BytesIO(b"\x03\x00\x00\x00\x00\x00\x00\x00abcdef"))
bytearray(b'abc')
>>> bigsize8 = struct.pack("<Q", sys.maxsize//3)
>>> read_bytearray8(io.BytesIO(bigsize8 + b"abcdef"))  #doctest: +ELLIPSIS
Traceback (most recent call last):
...
ValueError: expected ... bytes in a bytearray8, but only 6 remain
z'bytearray8 byte count > sys.maxsize: %dz5expected %d bytes in a bytearray8, but only %d remain)r9r`rar%r$r-�	bytearrayrVs&  r�read_bytearray8ri9sv��	�1�
�A���6�M�6��3�;�;���B�Q�F�G�G��6�6�!�9�D�
�4�y�A�~�����
�L���T��^�$�%�%r�
bytearray8z�A counted bytearray.

              The first argument is an 8-byte little-endian unsigned int giving
              the number of bytes, and the second argument is that many bytes.
              c��VP4pVPR4'g\R4hVRRp\VR4#)z]
>>> import io
>>> read_unicodestringnl(io.BytesIO(b"abc\\uabcd\njunk")) == 'abc\uabcd'
True
r>z4no newline found when trying to read unicodestringnlNzraw-unicode-escaper?)rBrCr%rr&s& r�read_unicodestringnlrl[sI��
�:�:�<�D��=�=�����+�,�	,����9�D��t�)�*�*r�unicodestringnlz�A newline-terminated Unicode string.

                      This is raw-unicode-escape encoded, so consists of
                      printable ASCII characters, and may contain embedded
                      escape sequences.
                      c��\V4pV^8�gQhVPV4p\V4V8Xd\VRR4#\	RV\V43,4h)a~
>>> import io
>>> s = 'abcd\uabcd'
>>> enc = s.encode('utf-8')
>>> enc
b'abcd\xea\xaf\x8d'
>>> n = bytes([len(enc)])  # little-endian 1-byte length
>>> t = read_unicodestring1(io.BytesIO(n + enc + b'junk'))
>>> s == t
True

>>> read_unicodestring1(io.BytesIO(n + enc[:-1]))
Traceback (most recent call last):
...
ValueError: expected 7 bytes in a unicodestring1, but only 6 remain
rM�
surrogatepassz9expected %d bytes in a unicodestring1, but only %d remain)r)r$r-rr%rVs&  r�read_unicodestring1rpusa��$	�1�
�A���6�M�6��6�6�!�9�D�
�4�y�A�~��4��/�2�2�
��!"�C��I��/�0�0r�unicodestring1aAA counted Unicode string.

                    The first argument is a 1-byte little-endian signed int
                    giving the number of bytes in the string, and the second
                    argument-- the UTF-8 encoding of the Unicode string --
                    contains that many bytes.
                    c��\V4pV^8�gQhV\P8�d\RV,4hVP	V4p\V4V8Xd\
VRR4#\RV\V43,4h)a�
>>> import io
>>> s = 'abcd\uabcd'
>>> enc = s.encode('utf-8')
>>> enc
b'abcd\xea\xaf\x8d'
>>> n = bytes([len(enc), 0, 0, 0])  # little-endian 4-byte length
>>> t = read_unicodestring4(io.BytesIO(n + enc + b'junk'))
>>> s == t
True

>>> read_unicodestring4(io.BytesIO(n + enc[:-1]))
Traceback (most recent call last):
...
ValueError: expected 7 bytes in a unicodestring4, but only 6 remain
z+unicodestring4 byte count > sys.maxsize: %drMroz9expected %d bytes in a unicodestring4, but only %d remain)r6r`rar%r$r-rrVs&  r�read_unicodestring4rs��}��$	�1�
�A���6�M�6��3�;�;���F��J�K�K��6�6�!�9�D�
�4�y�A�~��4��/�2�2�
��!"�C��I��/�0�0r�unicodestring4aAA counted Unicode string.

                    The first argument is a 4-byte little-endian signed int
                    giving the number of bytes in the string, and the second
                    argument-- the UTF-8 encoding of the Unicode string --
                    contains that many bytes.
                    c��\V4pV^8�gQhV\P8�d\RV,4hVP	V4p\V4V8Xd\
VRR4#\RV\V43,4h)a�
>>> import io
>>> s = 'abcd\uabcd'
>>> enc = s.encode('utf-8')
>>> enc
b'abcd\xea\xaf\x8d'
>>> n = bytes([len(enc)]) + b'\0' * 7  # little-endian 8-byte length
>>> t = read_unicodestring8(io.BytesIO(n + enc + b'junk'))
>>> s == t
True

>>> read_unicodestring8(io.BytesIO(n + enc[:-1]))
Traceback (most recent call last):
...
ValueError: expected 7 bytes in a unicodestring8, but only 6 remain
z+unicodestring8 byte count > sys.maxsize: %drMroz9expected %d bytes in a unicodestring8, but only %d remain)r9r`rar%r$r-rrVs&  r�read_unicodestring8rw�rtr�unicodestring8aBA counted Unicode string.

                    The first argument is an 8-byte little-endian signed int
                    giving the number of bytes in the string, and the second
                    argument-- the UTF-8 encoding of the Unicode string --
                    contains that many bytes.
                    c�X�\VRRR7pVR8XdR#VR8XdR#\V4#)z�
>>> import io
>>> read_decimalnl_short(io.BytesIO(b"1234\n56"))
1234

>>> read_decimalnl_short(io.BytesIO(b"1234L\n56"))
Traceback (most recent call last):
...
ValueError: invalid literal for int() with base 10: b'1234L'
F�rGrHs00s01T�rJr	�r'�ss& r�read_decimalnl_shortr~�s1��	�a��5�9�A�	�E�z��	
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>>> import io

>>> read_decimalnl_long(io.BytesIO(b"1234L\n56"))
1234

>>> read_decimalnl_long(io.BytesIO(b"123456789012345678901234L\n6"))
123456789012345678901234
FrzN�Lr?r{r|s& r�read_decimalnl_longr�s3��	�a��5�9�A����v��~�
�c�r�F���q�6�Mr�decimalnl_shorta�A newline-terminated decimal integer literal.

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                          is read.
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                         c�4�\VRRR7p\V4#)z?
>>> import io
>>> read_floatnl(io.BytesIO(b"-1.25\n6"))
-1.25
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              for infinities or NaNs).
              c��VP^4p\V4^8Xd\RV4^,#\R4h)z�
>>> import io, struct
>>> raw = struct.pack(">d", -1.25)
>>> raw
b'\xbf\xf4\x00\x00\x00\x00\x00\x00'
>>> read_float8(io.BytesIO(raw + b"\n"))
-1.25
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@�@r�float8aAn 8-byte binary representation of a float, big-endian.

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             strongly related to the IEEE-754 double format, and, in normal
             cases, is in fact identical to the big-endian 754 double format.
             On other boxes the dynamic range is limited to that of a 754
             double, and "add a half and chop" rounding is used to reduce
             the precision to 53 bits.  However, even on a 754 box,
             infinities, NaNs, and minus zero may not be handled correctly
             (may not survive roundtrip pickling intact).
             )�decode_longc��\V4pVPV4p\V4V8wd\R4h\	V4#)z�
>>> import io
>>> read_long1(io.BytesIO(b"\x00"))
0
>>> read_long1(io.BytesIO(b"\x02\xff\x00"))
255
>>> read_long1(io.BytesIO(b"\x02\xff\x7f"))
32767
>>> read_long1(io.BytesIO(b"\x02\x00\xff"))
-256
>>> read_long1(io.BytesIO(b"\x02\x00\x80"))
-32768
z'not enough data in stream to read long1)r)r$r-r%r�rVs&  r�
read_long1r�is<��	�1�
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�4�y�A�~��B�C�C��t��r�long1aA binary long, little-endian, using 1-byte size.

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    c��\V4pV^8d\RV,4hVPV4p\V4V8wd\R4h\	V4#)a7
>>> import io
>>> read_long4(io.BytesIO(b"\x02\x00\x00\x00\xff\x00"))
255
>>> read_long4(io.BytesIO(b"\x02\x00\x00\x00\xff\x7f"))
32767
>>> read_long4(io.BytesIO(b"\x02\x00\x00\x00\x00\xff"))
-256
>>> read_long4(io.BytesIO(b"\x02\x00\x00\x00\x00\x80"))
-32768
>>> read_long1(io.BytesIO(b"\x00\x00\x00\x00"))
0
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stackslicea�An object representing a contiguous slice of the stack.

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      and LONG then is that INT skips a trailing 'L', and produces a short
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      Another difference is due to that, when bool was introduced as a
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      Note that LONG takes time quadratic in the number of digits when
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      object instead.
      �BINBYTES�Bz�Push a Python bytes object.

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BINUNICODE�XaPush a Python Unicode string object.

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      �BINUNICODE8�aPush a Python Unicode string object.

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      �FLOAT�Fa�Newline-terminated decimal float literal.

      The argument is repr(a_float), and in general requires 17 significant
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      on most boxes).

      In general, FLOAT cannot be used to transport infinities, NaNs, or
      minus zero across boxes (or even on a single box, if the platform C
      library can't read the strings it produces for such things -- Windows
      is like that), but may do less damage than BINFLOAT on boxes with
      greater precision or dynamic range than IEEE-754 double.
      �BINFLOAT�Ga�Float stored in binary form, with 8 bytes of data.

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      cut it back to 53 significant bits).
      �
EMPTY_LIST�]zPush an empty list.�APPEND�az�Append an object to a list.

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      Stack before:  ... pylist markobject stackslice
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      although pylist is really extended in-place.
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      All the stack entries following the topmost markobject are placed into
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      �EMPTY_TUPLE�)zPush an empty tuple.�TUPLE�tavBuild a tuple out of the topmost stack slice, after markobject.

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      �TUPLE1�z�Build a one-tuple out of the topmost item on the stack.

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      �TUPLE2�aBuild a two-tuple out of the top two items on the stack.

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      �TUPLE3�aBuild a three-tuple out of the top three items on the stack.

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      �
EMPTY_DICT�}zPush an empty dict.�DICT�da�Build a dict out of the topmost stack slice, after markobject.

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      �SETITEMr}z�Add a key+value pair to an existing dict.

      Stack before:  ... pydict key value
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      The slice of the stack following the topmost markobject is taken as
      an alternating sequence of keys and values, added to the dict
      immediately under the topmost markobject.  Everything at and after the
      topmost markobject is popped, leaving the mutated dict at the top
      of the stack.

      Stack before:  ... pydict markobject key_1 value_1 ... key_n value_n
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      where pydict has been modified via pydict[key_i] = value_i for i in
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      �	EMPTY_SET�zPush an empty set.�ADDITEMS�a$Add an arbitrary number of items to an existing set.

      The slice of the stack following the topmost markobject is taken as
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      leaving the mutated set at the top of the stack.

      Stack before:  ... pyset markobject item_1 ... item_n
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      where pyset has been modified via pyset.add(item_i) = item_i for i in
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      �	FROZENSET�azBuild a frozenset out of the topmost slice, after markobject.

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      �POP�0z<Discard the top stack item, shrinking the stack by one item.�DUP�2z=Push the top stack item onto the stack again, duplicating it.�MARK�(z�Push markobject onto the stack.

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      �POP_MARK�1aPop all the stack objects at and above the topmost markobject.

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      that delimited their starting position on the stack.
      �GET�gz�Read an object from the memo and push it on the stack.

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      decimal string following.  BINGET and LONG_BINGET are space-optimized
      versions.
      �BINGET�hz�Read an object from the memo and push it on the stack.

      The index of the memo object to push is given by the 1-byte unsigned
      integer following.
      �LONG_BINGET�jz�Read an object from the memo and push it on the stack.

      The index of the memo object to push is given by the 4-byte unsigned
      little-endian integer following.
      �PUT�pz�Store the stack top into the memo.  The stack is not popped.

      The index of the memo location to write into is given by the newline-
      terminated decimal string following.  BINPUT and LONG_BINPUT are
      space-optimized versions.
      �BINPUTrIz�Store the stack top into the memo.  The stack is not popped.

      The index of the memo location to write into is given by the 1-byte
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      �LONG_BINPUT�rz�Store the stack top into the memo.  The stack is not popped.

      The index of the memo location to write into is given by the 4-byte
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      �MEMOIZE�z�Store the stack top into the memo.  The stack is not popped.

      The index of the memo location to write is the number of
      elements currently present in the memo.
      �EXT1�a�Extension code.

      This code and the similar EXT2 and EXT4 allow using a registry
      of popular objects that are pickled by name, typically classes.
      It is envisioned that through a global negotiation and
      registration process, third parties can set up a mapping between
      ints and object names.

      In order to guarantee pickle interchangeability, the extension
      code registry ought to be global, although a range of codes may
      be reserved for private use.

      EXT1 has a 1-byte integer argument.  This is used to index into the
      extension registry, and the object at that index is pushed on the stack.
      �EXT2�zNExtension code.

      See EXT1.  EXT2 has a two-byte integer argument.
      �EXT4�zOExtension code.

      See EXT1.  EXT4 has a four-byte integer argument.
      �GLOBAL�ca�Push a global object (module.attr) on the stack.

      Two newline-terminated strings follow the GLOBAL opcode.  The first is
      taken as a module name, and the second as a class name.  The class
      object module.class is pushed on the stack.  More accurately, the
      object returned by self.find_class(module, class) is pushed on the
      stack, so unpickling subclasses can override this form of lookup.
      �STACK_GLOBAL�z7Push a global object (module.attr) on the stack.
      �REDUCE�RaLPush an object built from a callable and an argument tuple.

      The opcode is named to remind of the __reduce__() method.

      Stack before: ... callable pytuple
      Stack after:  ... callable(*pytuple)

      The callable and the argument tuple are the first two items returned
      by a __reduce__ method.  Applying the callable to the argtuple is
      supposed to reproduce the original object, or at least get it started.
      If the __reduce__ method returns a 3-tuple, the last component is an
      argument to be passed to the object's __setstate__, and then the REDUCE
      opcode is followed by code to create setstate's argument, and then a
      BUILD opcode to apply  __setstate__ to that argument.

      If not isinstance(callable, type), REDUCE complains unless the
      callable has been registered with the copyreg module's
      safe_constructors dict, or the callable has a magic
      '__safe_for_unpickling__' attribute with a true value.  I'm not sure
      why it does this, but I've sure seen this complaint often enough when
      I didn't want to <wink>.
      �BUILD�ba�Finish building an object, via __setstate__ or dict update.

      Stack before: ... anyobject argument
      Stack after:  ... anyobject

      where anyobject may have been mutated, as follows:

      If the object has a __setstate__ method,

          anyobject.__setstate__(argument)

      is called.

      Else the argument must be a dict, the object must have a __dict__, and
      the object is updated via

          anyobject.__dict__.update(argument)
      �INST�iaqBuild a class instance.

      This is the protocol 0 version of protocol 1's OBJ opcode.
      INST is followed by two newline-terminated strings, giving a
      module and class name, just as for the GLOBAL opcode (and see
      GLOBAL for more details about that).  self.find_class(module, name)
      is used to get a class object.

      In addition, all the objects on the stack following the topmost
      markobject are gathered into a tuple and popped (along with the
      topmost markobject), just as for the TUPLE opcode.

      Now it gets complicated.  If all of these are true:

        + The argtuple is empty (markobject was at the top of the stack
          at the start).

        + The class object does not have a __getinitargs__ attribute.

      then we want to create an old-style class instance without invoking
      its __init__() method (pickle has waffled on this over the years; not
      calling __init__() is current wisdom).  In this case, an instance of
      an old-style dummy class is created, and then we try to rebind its
      __class__ attribute to the desired class object.  If this succeeds,
      the new instance object is pushed on the stack, and we're done.

      Else (the argtuple is not empty, it's not an old-style class object,
      or the class object does have a __getinitargs__ attribute), the code
      first insists that the class object have a __safe_for_unpickling__
      attribute.  Unlike as for the __safe_for_unpickling__ check in REDUCE,
      it doesn't matter whether this attribute has a true or false value, it
      only matters whether it exists (XXX this is a bug).  If
      __safe_for_unpickling__ doesn't exist, UnpicklingError is raised.

      Else (the class object does have a __safe_for_unpickling__ attr),
      the class object obtained from INST's arguments is applied to the
      argtuple obtained from the stack, and the resulting instance object
      is pushed on the stack.

      NOTE:  checks for __safe_for_unpickling__ went away in Python 2.3.
      NOTE:  the distinction between old-style and new-style classes does
             not make sense in Python 3.
      �OBJ�oa�Build a class instance.

      This is the protocol 1 version of protocol 0's INST opcode, and is
      very much like it.  The major difference is that the class object
      is taken off the stack, allowing it to be retrieved from the memo
      repeatedly if several instances of the same class are created.  This
      can be much more efficient (in both time and space) than repeatedly
      embedding the module and class names in INST opcodes.

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      gathered into an argument tuple, and then the logic seems identical,
      except that no __safe_for_unpickling__ check is done (XXX this is
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R8XgQh^pEL�i;i)a�Produce a symbolic disassembly of a pickle.

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the first STOP opcode encountered.

Optional arg 'out' is a file-like object to which the disassembly is
printed.  It defaults to sys.stdout.

Optional arg 'memo' is a Python dict, used as the pickle's memo.  It
may be mutated by dis(), if the pickle contains PUT or BINPUT opcodes.
Passing the same memo object to another dis() call then allows disassembly
to proceed across multiple pickles that were all created by the same
pickler with the same memo.  Ordinarily you don't need to worry about this.

Optional arg 'indentlevel' is the number of blanks by which to indent
a new MARK level.  It defaults to 4.

Optional arg 'annotate' if nonzero instructs dis() to add short
description of the opcode on each line of disassembled output.
The value given to 'annotate' must be an integer and is used as a
hint for the column where annotation should start.  The default
value is 0, meaning no annotations.

In addition to printing the disassembly, some sanity checks are made:

+ All embedded opcode arguments "make sense".

+ Explicit and implicit pop operations have enough items on the stack.

+ When an opcode implicitly refers to a markobject, a markobject is
  actually on the stack.

+ A memo entry isn't referenced before it's defined.

+ The markobject isn't stored in the memo.
NrRz%5d:)�end�file�4rz(MARK at unknown opcode offset)z(MARK at %d)zno MARK exists on stackrz(as %d)z'stack is empty -- can't store into memoz"can't store markobject in the memoz&memo key %r has never been stored intorB)r~z3tries to pop %d items from stack with only %d itemsz highest protocol among opcodes =zstack not empty after STOP: %rr?)rrrr)rrr)r�r�r�)rcrH�reprr�r-r�maxr�r�r��
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>>> import pickle
>>> x = [1, 2, (3, 4), {b'abc': "def"}]
>>> pkl0 = pickle.dumps(x, 0)
>>> dis(pkl0)
    0: (    MARK
    1: l        LIST       (MARK at 0)
    2: p    PUT        0
    5: I    INT        1
    8: a    APPEND
    9: I    INT        2
   12: a    APPEND
   13: (    MARK
   14: I        INT        3
   17: I        INT        4
   20: t        TUPLE      (MARK at 13)
   21: p    PUT        1
   24: a    APPEND
   25: (    MARK
   26: d        DICT       (MARK at 25)
   27: p    PUT        2
   30: c    GLOBAL     '_codecs encode'
   46: p    PUT        3
   49: (    MARK
   50: V        UNICODE    'abc'
   55: p        PUT        4
   58: V        UNICODE    'latin1'
   66: p        PUT        5
   69: t        TUPLE      (MARK at 49)
   70: p    PUT        6
   73: R    REDUCE
   74: p    PUT        7
   77: V    UNICODE    'def'
   82: p    PUT        8
   85: s    SETITEM
   86: a    APPEND
   87: .    STOP
highest protocol among opcodes = 0

Try again with a "binary" pickle.

>>> pkl1 = pickle.dumps(x, 1)
>>> dis(pkl1)
    0: ]    EMPTY_LIST
    1: q    BINPUT     0
    3: (    MARK
    4: K        BININT1    1
    6: K        BININT1    2
    8: (        MARK
    9: K            BININT1    3
   11: K            BININT1    4
   13: t            TUPLE      (MARK at 8)
   14: q        BINPUT     1
   16: }        EMPTY_DICT
   17: q        BINPUT     2
   19: c        GLOBAL     '_codecs encode'
   35: q        BINPUT     3
   37: (        MARK
   38: X            BINUNICODE 'abc'
   46: q            BINPUT     4
   48: X            BINUNICODE 'latin1'
   59: q            BINPUT     5
   61: t            TUPLE      (MARK at 37)
   62: q        BINPUT     6
   64: R        REDUCE
   65: q        BINPUT     7
   67: X        BINUNICODE 'def'
   75: q        BINPUT     8
   77: s        SETITEM
   78: e        APPENDS    (MARK at 3)
   79: .    STOP
highest protocol among opcodes = 1

Exercise the INST/OBJ/BUILD family.

>>> import pickletools
>>> dis(pickle.dumps(pickletools.dis, 0))
    0: c    GLOBAL     'pickletools dis'
   17: p    PUT        0
   20: .    STOP
highest protocol among opcodes = 0

>>> from pickletools import _Example
>>> x = [_Example(42)] * 2
>>> dis(pickle.dumps(x, 0))
    0: (    MARK
    1: l        LIST       (MARK at 0)
    2: p    PUT        0
    5: c    GLOBAL     'copy_reg _reconstructor'
   30: p    PUT        1
   33: (    MARK
   34: c        GLOBAL     'pickletools _Example'
   56: p        PUT        2
   59: c        GLOBAL     '__builtin__ object'
   79: p        PUT        3
   82: N        NONE
   83: t        TUPLE      (MARK at 33)
   84: p    PUT        4
   87: R    REDUCE
   88: p    PUT        5
   91: (    MARK
   92: d        DICT       (MARK at 91)
   93: p    PUT        6
   96: V    UNICODE    'value'
  103: p    PUT        7
  106: I    INT        42
  110: s    SETITEM
  111: b    BUILD
  112: a    APPEND
  113: g    GET        5
  116: a    APPEND
  117: .    STOP
highest protocol among opcodes = 0

>>> dis(pickle.dumps(x, 1))
    0: ]    EMPTY_LIST
    1: q    BINPUT     0
    3: (    MARK
    4: c        GLOBAL     'copy_reg _reconstructor'
   29: q        BINPUT     1
   31: (        MARK
   32: c            GLOBAL     'pickletools _Example'
   54: q            BINPUT     2
   56: c            GLOBAL     '__builtin__ object'
   76: q            BINPUT     3
   78: N            NONE
   79: t            TUPLE      (MARK at 31)
   80: q        BINPUT     4
   82: R        REDUCE
   83: q        BINPUT     5
   85: }        EMPTY_DICT
   86: q        BINPUT     6
   88: X        BINUNICODE 'value'
   98: q        BINPUT     7
  100: K        BININT1    42
  102: s        SETITEM
  103: b        BUILD
  104: h        BINGET     5
  106: e        APPENDS    (MARK at 3)
  107: .    STOP
highest protocol among opcodes = 1

Try "the canonical" recursive-object test.

>>> L = []
>>> T = L,
>>> L.append(T)
>>> L[0] is T
True
>>> T[0] is L
True
>>> L[0][0] is L
True
>>> T[0][0] is T
True
>>> dis(pickle.dumps(L, 0))
    0: (    MARK
    1: l        LIST       (MARK at 0)
    2: p    PUT        0
    5: (    MARK
    6: g        GET        0
    9: t        TUPLE      (MARK at 5)
   10: p    PUT        1
   13: a    APPEND
   14: .    STOP
highest protocol among opcodes = 0

>>> dis(pickle.dumps(L, 1))
    0: ]    EMPTY_LIST
    1: q    BINPUT     0
    3: (    MARK
    4: h        BINGET     0
    6: t        TUPLE      (MARK at 3)
    7: q    BINPUT     1
    9: a    APPEND
   10: .    STOP
highest protocol among opcodes = 1

Note that, in the protocol 0 pickle of the recursive tuple, the disassembler
has to emulate the stack in order to realize that the POP opcode at 16 gets
rid of the MARK at 0.

>>> dis(pickle.dumps(T, 0))
    0: (    MARK
    1: (        MARK
    2: l            LIST       (MARK at 1)
    3: p        PUT        0
    6: (        MARK
    7: g            GET        0
   10: t            TUPLE      (MARK at 6)
   11: p        PUT        1
   14: a        APPEND
   15: 0        POP
   16: 0        POP        (MARK at 0)
   17: g    GET        1
   20: .    STOP
highest protocol among opcodes = 0

>>> dis(pickle.dumps(T, 1))
    0: (    MARK
    1: ]        EMPTY_LIST
    2: q        BINPUT     0
    4: (        MARK
    5: h            BINGET     0
    7: t            TUPLE      (MARK at 4)
    8: q        BINPUT     1
   10: a        APPEND
   11: 1        POP_MARK   (MARK at 0)
   12: h    BINGET     1
   14: .    STOP
highest protocol among opcodes = 1

Try protocol 2.

>>> dis(pickle.dumps(L, 2))
    0: \x80 PROTO      2
    2: ]    EMPTY_LIST
    3: q    BINPUT     0
    5: h    BINGET     0
    7: \x85 TUPLE1
    8: q    BINPUT     1
   10: a    APPEND
   11: .    STOP
highest protocol among opcodes = 2

>>> dis(pickle.dumps(T, 2))
    0: \x80 PROTO      2
    2: ]    EMPTY_LIST
    3: q    BINPUT     0
    5: h    BINGET     0
    7: \x85 TUPLE1
    8: q    BINPUT     1
   10: a    APPEND
   11: 0    POP
   12: h    BINGET     1
   14: .    STOP
highest protocol among opcodes = 2

Try protocol 3 with annotations:

>>> dis(pickle.dumps(T, 3), annotate=1)
    0: \x80 PROTO      3 Protocol version indicator.
    2: ]    EMPTY_LIST   Push an empty list.
    3: q    BINPUT     0 Store the stack top into the memo.  The stack is not popped.
    5: h    BINGET     0 Read an object from the memo and push it on the stack.
    7: \x85 TUPLE1       Build a one-tuple out of the topmost item on the stack.
    8: q    BINPUT     1 Store the stack top into the memo.  The stack is not popped.
   10: a    APPEND       Append an object to a list.
   11: 0    POP          Discard the top stack item, shrinking the stack by one item.
   12: h    BINGET     1 Read an object from the memo and push it on the stack.
   14: .    STOP         Stop the unpickling machine.
highest protocol among opcodes = 2

a=
>>> import pickle
>>> import io
>>> f = io.BytesIO()
>>> p = pickle.Pickler(f, 2)
>>> x = [1, 2, 3]
>>> p.dump(x)
>>> p.dump(x)
>>> f.seek(0)
0
>>> memo = {}
>>> dis(f, memo=memo)
    0: \x80 PROTO      2
    2: ]    EMPTY_LIST
    3: q    BINPUT     0
    5: (    MARK
    6: K        BININT1    1
    8: K        BININT1    2
   10: K        BININT1    3
   12: e        APPENDS    (MARK at 5)
   13: .    STOP
highest protocol among opcodes = 2
>>> dis(f, memo=memo)
   14: \x80 PROTO      2
   16: h    BINGET     0
   18: .    STOP
highest protocol among opcodes = 2
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